In triangle ABC, E and D are two points lying on AB and AC respectively such that CE and BD - Maths - Triangles

Question

In triangle ABC, E and D are two points lying on AB and
AC respectively such that CE and BD intersect each
other at O If triangle AEC congreunt CDB, then triangle ABC will
always
be a/an
(1) Obtuse-angled triangle
(2) Scalene triangle
(3) Isosceles right-angled triangle
(4) Equilateral triangle

Brijendra Pal · Accepted Answer

Hi,

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Here triangle AEC and CDB are congruent so AE = CD , EC = BD and AC = BCAlso angle EAC = angle DCB  now take AC = BC means angle CAB = angle CBA so it has all angles equal so it is a equilateral triangle

In triangle ABC, E and D are two points lying on AB and AC respectively such that CE and BD intersect each other at O. If triangle AEC congreunt CDB, then triangle ABC will always be a/an (1) Obtuse-angled triangle (2) Scalene triangle (3) Isosceles right-angled triangle (4) Equilateral triangle

In triangle ABC, E and D are two points lying on AB and
AC respectively such that CE and BD intersect each
other at O. If triangle AEC congreunt CDB, then triangle ABC will always
be a/an
(1) Obtuse-angled triangle
(2) Scalene triangle
(3) Isosceles right-angled triangle
(4) Equilateral triangle