in triangle ABC, side BC is produced  to D TO FORM EXTERIOR ANGLE ACD 
IF ANGLE ACD =130 DEGREE AND ANGLE ABC = 50 DEGREE ,FIND ANGLE BAC AND ACB

Dear student


Given: ACD=130°and ABC=50°Now ACD+ACB=180°    Linear pair130°+ACB=180°ACB=180°-130°ACB=50°Now consider ABC, by angle sum propertyABC+BCA+CAB=180°50°+50°+CAB=180°CAB=180°-100°CAB=80°
Regards

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can you sen a figure for the same
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mnxsvmiyesv
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