in triangle ABC the bisector of angle B meets AC at D A line PQ parallel to AC - Maths - Triangles

Question

in triangle ABC the bisector of angle B meets AC at D A line PQ
parallel to AC meets AB , BC and BD at P ,Q and R respectively show
that PR*BQ = QR * BP please someone i need it fast

Sujata Bhuyan · Answer

In tringle BRQ and triangle BRP,
angle B is an common angle 1
angle R is also an common angle 2
therefore,triangle BRQ is proportion to triangle BRP (AA
congruence)
therefore,BQ/BP=QR/RP
PR*BQ=QR*BP
Proved

in triangle ABC the bisector of angle B meets AC at D . A line PQ parallel to AC meets AB , BC and BD at P ,Q and R respectively . show that PR*BQ = QR * BP. please someone i need it fast

in triangle ABC the bisector of angle B meets AC at D . A line PQ parallel to AC meets AB , BC and BD at P ,Q and R respectively . show that PRBQ = QR BP. please someone i need it fast