In triangle ABC we have angle A=100 and angles B=C=40. The side AB is produced to a point D so that B lies between A and D and AD=AC. Find angle BCD Share with your friends Share 0 Shruti Tyagi answered this Dear student, Since AD=AC⇒∠ACD=∠CDA --[angles opposite to equal sides are equal]In ∆ACD∠ACD+∠CDA+∠CAD=180°⇒x+x+100°=180°⇒2x=180°-100°⇒2x=80°⇒x=80°2⇒x=40°⇒∠ACD=40°But this is not possible as ∠ACB=40° (given)Recheck your post and get back to us for meanigful help. Regards -1 View Full Answer