In triangle ABE, AE = BE.Circle through A and B intersects AE and BE at D and C respectively.prove that DC parallel to AB. plz solve my problem

DC || AB, if ∠EAB = ∠EDC

In ΔABE,

AE = BE

⇒ ∠EAB = ∠EBA ... (1)

As exterior angle of a cyclic quadrilateral is equal to opposite interior angle.

∴ ∠EDC = ∠EBA ... (ii)

From (1) and (2)

∠EAB = ∠EDC

∴ DC || AB