in triangle BCA ,AB=BC, BX=BY.2 points on lines BA and BC.show that AX=CY.state the axiom used
AB=BC
AX+BX = BY+CY
AX + BY = BY+CY ( because BX = BY)
Subtracting BY from both sides we get
AX = CY
Hence Proved
in triangle BCA ,AB=BC, BX=BY.2 points on lines BA and BC.show that AX=CY.state the axiom used
AB=BC
AX+BX = BY+CY
AX + BY = BY+CY ( because BX = BY)
Subtracting BY from both sides we get
AX = CY
Hence Proved