​in triangle PQR, PS is the bisector of angle QPR. ST is perpendicular PR and SU is perpendicular PQ. Prove that PT=PU

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  • -1
IN PQR,
2 TRIANGLES ARE FORMED:PST AND PSU WHICH ARE CONGRUENT BY ASA CRITERIA
i.e. ANGLE QPS = ANGLE SPR
​SIDE PS(COMMON)
ANGLE PST = ANGLE PSU (PERPENDICULAR)
SO THIRD ANGLE PUS (WILL ALSO BE) = PTS
​DUE TO THEIR CONGRUENCY PT (WILL ALSO BE) = PU
SO,PROVED......
  • 2
IN PQR,
2 TRIANGLES ARE FORMED:PST AND PSU WHICH ARE CONGRUENT BY ASA CRITERIA
i.e. ANGLE QPS = ANGLE SPR
​SIDE PS(COMMON)
ANGLE PST = ANGLE PSU (PERPENDICULAR)
SO THIRD ANGLE PUS (WILL ALSO BE) = PTS
​DUE TO THEIR CONGRUENCY PT (WILL ALSO BE) = PU
SO,PROVED......
  • 0
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