In which one of the following species the central atom has the type of hybridisation which is not the same as that present in the other three ? (a) SF4 (b) I- 3 (c) SbCl 2- 5 (d) PCl5 Share with your friends Share 3 Vartika Jain answered this Dear Student, Number of hybrid orbitals =12(Number of valence electrons+ No. of atoms attached to the central metal atom +magnitude of negative charge-magnitude of positive charge)if hybrid orbitals is 2=sp3=sp24=sp35=sp3d6=sp3d2(a) SF4No. of hybrid orbitals=12(6+4+0-0)=5 = sp3d(b) I3-No. of hybrid orbitals=12(7+2+1-0)=5 = sp3d(c) SbCl52-No. of hybrid orbitals=12(5+5+2-0)=6= sp3d2(d) PCl5No. of hybrid orbitals=12(5+5+0-0)=5 = sp3dHence, the correct answer is (C) 13 View Full Answer Nishtha Gahlot answered this c) SbCl52- . rest of them sp3d hybridisation. you can find the type of hybridisation by calculating the no. of lone pairs and bond pairs and adding them. a) SF4 - 6+4*7/8=34/8 remainder=2,quotient=4 no. of lone pairs=2/2=1 no. of bond pairs=4 no. of B.P +no. of LP=4+1=5=sp3d you can follow the same steps to find the hybridisation of the other compounds. 3
