In young's double slit exp, the fringe width is found to be 0 4mm If the whole apparatus is - Physics - Wave Optics

Question

In young's double slit exp, the fringe width is found to be 0
4mm If the whole apparatus is immersed in water of refractive index
4/3 without disturbing the geometrical arrangement, what will be
the new fringe width ??

Kranav Sharma · Accepted Answer

The new fringe width (Î²') is related to the old
fringe width (Î²) as
Î²' = Î² / Î¼
where
Î¼ = refractive index of media = 4/3
and
Î² =0 4mm
so,
Î²' = 0 4 / (4/3)
thus, we get
Î²' = 0 3mm

In young's double slit exp, the fringe width is found to be 0.4mm. If the whole apparatus is immersed in water of refractive index 4/3 without disturbing the geometrical arrangement, what will be the new fringe width ??