# integral 0 to 1 x(tan-1x)2dx

$\frac{{x}^{2}}{2}{\left({\mathrm{tan}}^{-1}x\right)}^{2}+x\mathrm{tan}-1x-\frac{1}{2}\mathrm{ln}\left(1+{x}^{2}\right)+\frac{{\left({\mathrm{tan}}^{-1}x\right)}^{2}}{2}$
Evaluating this from 0 to 1 we get that:

• -14

pi/2-log2

• 1

take 2 as second function and tan-1x as first functions and then solve by

By parts

• -1
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