integrate(limit e2 to e)  log x dx

Dear Student,
Please find below the solution to the asked query:

I=ee2 logx.dx=ee2 1.logx.dxUse integration by parts, we getI= logx1.dxee2-ee2 ddxlogx1.dxdx= x logxee2-ee2 1xxdx= x logxee2-ee2 1.dx=e2 loge2-eloge-xee2=2e2 loge-e-e2-e=2e2 -e-e2+e=e2 Answer

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