Integrate cos(2x)/[(sinx+ cosx)2] Answer with explanation. Share with your friends Share 0 Varun.Rawat answered this Let I = ∫cos 2xsin x + cos x2 dx=∫cos2x - sin2xsin x + cos x2 dx as, cos 2x = cos2x - sin2x=∫cos x + sin xcos x - sin xsin x + cos x2 dx=∫cos x - sin xsin x + cos x dxPut sin x + cos x = t⇒cos x - sin xdx = dtSo, I = ∫dtt = logt + C = logsin x + cos x + C 0 View Full Answer