integration cosx-sinx/7-9sin2x dx Share with your friends Share 3 Manbar Singh answered this Let I = ∫cos x - sin x7 - 9 sin 2x dx=∫cos x - sin x7 - 9sin x + cos x2 - 1 dx=∫cos x - sin x16 - 9sin x + cos x2 dxput sin x + cos x = t⇒cos x - sin xdx = dtso, I = ∫dt16 - 9t2=19∫dt169-t2=19∫dt4/32 -t2=19 × 12×43 log4/3+t4/3-t + C=124 log4 + 3t4-3t + C=124log4 + 3 sin x + 3 cos x4 - 3 sin x - 3 cos x + C 1 View Full Answer
