integration of x2+x+1/x2-x+1dx x2=xsquare Share with your friends Share 2 Anuradha Sharma answered this ∫x2+x+1x2-x+1dx=∫x2-x+1+2xx2-x+1dx=∫x2-x+1x2-x+1dx+∫2xx2-x+1dx=∫dx+∫2x-1+1x2-x+1dx=x+∫2x-1x2-x+1dx+∫1x2-x+1dx=x+logx2-x+1+∫1x2-x+14-14+1dx=x+logx2-x+1+∫dxx-122+322=x+logx2-x+1+132tan-1x-1232+C 0 View Full Answer