Dear student, The hydrolysis of cane sugar is : t = 0 sec a mol / L 0 0 Cane sugar + water →H+ Glucose + Fructose t = t sec (a - x) mol /L x mol / L x mol / L t = ∞ sec 0 mol / L a mol / L a mol / L Now : x = r0 - rt and a = r0 - r∞ Then From the formula of rate constant of first order K = 2 303 / t log { a / a-x } or K = 2 303 / t log {( r0 - r∞) / ( rt - r∞) } option (2) Regards,

Inversion of a sugar

Inversion of a sugar betweenAand B increases by a factor of 100, d reætbn with respect to A is (314 [412 ræ#on 2NC(g) • Hi(g) N70(g) • Hao at 900 K following data are observed 0075 0150 of NO (atm) Initial pressure Of H, (atm) O, 40 040 020 initial rate of pressure (atm min-') 0020 0005 0010 hd out the rate law and order of reaction of a sugar follows first order rate equation which can tojidwed by nothing the change in rotation of ofpolanzation of light in the polarimeter Iff. r, at t z t t and t 0. then, first 31B* t In of tt•w following is an unimolecu!aöc t112H1 121 N • i Oz 131 H, 2HCi (41 pcla • PCI,

Dear student,

The hydrolysis of cane sugar is :
t = 0 sec. a mol / L 0 0
Cane sugar + water

\overset{H^{+}}{\to}

Glucose + Fructose
t = t sec. (a - x) mol /L x mol / L x mol / L
t = ∞ sec. 0 mol / L a mol / L a mol / L
Now : x = r₀ - r_t and a = r₀ - r∞
Then From the formula of rate constant of first order K = 2.303 / t log { a / a-x }
or K = 2.303 / t log {( r₀ - r_∞) / ( r_t - r_∞) } option (2)
Regards,

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