Ionization energy of He+ is 19 6 x 10-18 J atom-1 The energy of the first stationary state - Chemistry - Atomic Structure

Question

Ionization energy of He+ is 19 6 x 10-18 J
atom-1 The energy of the first stationary state ( n=1 )
of Li2+ is ?

Yasodharan · Accepted Answer

Dear Student,

The computation are performed below,

Ionization energy of He+ = 19
6×10-18 J atom-1so
,First stationary energy of He+= -19
6×10-18 J atom-1For Helium Z =2,         En(He+)=2π2Z2Heme4n2h2   → eq
(1)For Lithium Z = 3,        En(Li2+)=2π2Z2Lime4n2h2   → eq
(2)dividing eq (2) by eq
(1) we get,     En(Li2)En(He+)=2π2Z2Lime4n2h22π2Z2Heem4n2h2=Z2LiZ2He⇒E1(Li2)=Z2LiZ2He×E1(He+)         =3222×(-19
8×10-18 J atom-1)            = -44
1×10-18  J atom-1 
Regards

Ionization energy of He+ is 19.6 x 10-18 J atom-1 . The energy of the first stationary state ( n=1 ) of Li2+ is....?

Ionization energy of He⁺ is 19.6 x 10^-18 J atom^-1. The energy of the first stationary state ( n=1 ) of Li²⁺ is....?