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Is it possible to have an equation 2sin²X-cosX+4=0

$2 (1 - \cos^{2} x) - \cos x + 4 = 0 2 - 2 \cos^{2} x - \cos x + 4 = 0 - 2 \cos^{2} x - \cos x + 6 = 0 2 \cos^{2} x + \cos x - 6 = 0 2 \cos^{2} x + 4 \cos x - 3 \cos x - 6 = 0 2 \cos x (\cos x + 2) - 3 (\cos x + 2) = 0 (2 \cos x - 3) (\cos x + 2) = 0 \cos x = \frac{3}{2} a n d \cos x = - 2$

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