It is a question from states of matter (Q 36) - Chemistry - The Solid State

Question

It is a question from states of matter (Q 36)

Kushal Kumar · Accepted Answer

Dear Student
initial pressure = nRT/V= 1 x 0
0821 x400/16
42=2 atmNow let us assume that final pressure is Pand that number of moles in container A is n1 and that in B is n2So initial moles = n1 + n21 = PV1/RT1 + PV2/RT2Here V1=16
42 litres, V2=8
21 litresT1=400K , T2=300KR=0
0821substituing we get1= P(16 42/(0
0821X400) + 8 21/(0
0821 x 300))1= P x0
083(a)⇒P = 1
2 atm(b)Number of moles in container B=n2=1
2 x 8 21/(0 0821x300) = 0
4 moels(c)collision frequency is directly proportional to THence ratio of collisions = ratio of collision frequency = 400/300 = 1
15
Regards