it is desired to prepare 500 g of 10 % mass by mass percentage of urea in water how - Science - Is Matter Around Us Pure

Question

it is desired to prepare 500 g of 10 % mass by mass percentage
of urea in water how much urea should be dissolved in how much
volume of water ? density of water is 1 g mL-1

Kirti Gogia · Accepted Answer

The mass by mass percentage of a solution is given by the
following relation
mass by mass percentage of a solution = (mass of solute / mass
of solution) X 100
where mass of the solution = mass of solute + mass of
solvent
We have to prepare 500g of 10% mass by mass percent solution of
urea in water Let the mass of urea required be 'a' grams
Therefore
(a / 500) X 100 = 10
Solving for a, we get
a = 50g
Thus, mass of urea is 50g So, mass of water will be
= mass of solution - mass of urea
= (500 - 50)g = 450g
Since the density of water is given to be 1gml-1, therefore the
volume of water required would be
= mass of water / density of water
= 450 / 1 = 450 ml
Hence the mass of urea required would be 50g and the volume of
water required would be 450 ml

it is desired to prepare 500 g of 10 % mass by mass percentage of urea in water. how much urea should be dissolved in how much volume of water ? density of water is 1 g mL-1.

it is desired to prepare 500 g of 10 % mass by mass percentage of urea in water. how much urea should be dissolved in how much volume of water ? density of water is 1 g mL^-1.