Johan used a thermometer having 20 divisions between 30 degree Celsius and 40 degree Celsius mark. While determining the boiling point of water using this thermometre he observed that the level of mercury becomes constant just 3 divisions below the 100 degree Celsius mark. Johan should record in his notebook

a) Least Count = 0.5 degree Celsius, Boiling Point = 97 degree Celsius

b) L.C = 0.5 degree Celsius, B.P = 98.5 degree Celsius

c) L.C = 1 degree Celsius, B.P = 98.5 degree Celsius d) L.C = 1 degree Celsius, B.P = 97 degree Celsius

Correct option:  b)

Here,

20 division for (40 – 30)0C = 100C

1 division for 10/200C = 0.50C

So L.C. = 0.5 0C

Now 3 division of the thermometer  = 0.5 × 3

  =  1.50C

So the boiling point of water will be (100 – 1.5)0C = 98.50C

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