John is riding the Giant Drop at Canada. If John free falls for 2.6 seconds, what will be his final velocity and how far will he fall? In this question how u = 0??? V=0 ryt? because he is riding so he has motion. and after falling , he will come in rest ryt? Plz explain
Dear Student,
Given,
John is undergoing a free fall. So, John will fall under the action of uniform acceleration g = 9.8 ms-2.
Also, initial velocity, u = 0.
After t = 2.6 s
Let the velocity attained after t = 2.6 m/s be v.
Then,
Using the relation:
Let it fall by a distance d.
Using another equation of motion:
Regards