Kindly help me in q 16

Solution:

According to Ohm's law:

V = I R \Rightarrow I = \frac{1}{R} \times V Which is of the form of a straight line, y = m x whose slope is m = \frac{1}{R} In the given graph, m_{2} < m_{1} < m_{3} \Rightarrow \frac{1}{R_{2}} < \frac{1}{R_{1}} < \frac{1}{R_{3}} \Rightarrow R_{2} > R_{1} > R_{3} In other way, for a given voltage current is maximum in wire 3 > wire 1 > wire 2 So, resistance, R_{3} < R_{1} < R_{2} i . e ., R_{2} > R_{1} > R_{3} (∵ For a given voltage, I \propto \frac{1}{R}) Hence, the correct answer is option (c) .