Kindly help me to solve this question.
The distance-time graph of two buses is shown below. The buses start simultaneously in the same direction:
(a) How much ahead of A is B when the motion starts?
(b) What is the speed of B?
(c) When and where will A catch B?
(d) What is the difference between the speeds of A and B?
(e) Is the motion of both the buses uniform or non uniform? Justify your answer.
Dear Student
In the above graph
(a)100 km ahead of A is B when motion starts.
(b)Speed of B = (150-100)/2 = 50/2 = 25 km/hour
(c)At Q after 2 hours of starting journey A catch B.
(d) Speed of A = 150/2 = 75 km/hour. So difference of speed is 50 km/hour
(e)The motions of both the busses is uniform as they follow a straight line so their speed is same in all time so motion is uniform.
N.B- speed = distance/time
In the above graph
(a)100 km ahead of A is B when motion starts.
(b)Speed of B = (150-100)/2 = 50/2 = 25 km/hour
(c)At Q after 2 hours of starting journey A catch B.
(d) Speed of A = 150/2 = 75 km/hour. So difference of speed is 50 km/hour
(e)The motions of both the busses is uniform as they follow a straight line so their speed is same in all time so motion is uniform.
N.B- speed = distance/time