Kindly solve.. this is a meritnstion question but i doubt it's solution... pls refer

​Q5. Three distinct points A, B and C are given in the 2 - dimensional coordinate plane such that the ratio of distance of any one of them from the point (1,0) to the distance from the point (– 1, 0) is equal to $\frac{1}{3}$. Then the circumcvented of the triangle ABC is at the point

   (A)  ( 0, 0)


   (B)  $\left(\frac{5}{4},0\right)$


  (C)  $\left(\frac{5}{2},0\right)$


  (D) $\left(\frac{5}{3},0\right)$