Kindly solve this..

Dear Student
If we resolve force vectors along x axis and y axis then along x axis we get 
4 cos 30 and 6 cos 45.

So  resultant force along x axis is

$$\begin{gathered} F_x = 4 \cos 30 +6 \cos 45 \\ {F}_x = 4\times \frac{\sqrt{3}}{2} +6\times \frac{1}{\sqrt{2}} \\ {F}_x = 2\sqrt{3} +\frac{6}{\sqrt{2}} \end{gathered}$$
Regards