Kp for the reaction,MgCO3(s)→MgO(s)+CO2(g)is 9×10-10 Calculate ∆G for the reaction at 25 C - Chemistry -

Question

K p   f o r   t h e   r e a c t i o n , M g C O 3 (
s ) → M g O ( s ) + C O 2 ( g ) i s   9 × 10 - 10
  C a l c u l a t e   ∆ G °   f o r  
t h e   r e a c t i o n   a t   25 ° C

Vartika Jain · Accepted Answer

Dear Student,

We know that,∆G°=-RTln KpR=8
314 JK-1mol-1T=25°C=25+273=298 KSo, ∆G°=-8
314×298 ×ln (9×10-10)                =-8
314×298 × (2
19-10)                =19349
8 J                =19
3498 kJ

K p f o r t h e r e a c t i o n , M g C O 3 ( s ) → M g O ( s ) + C O 2 ( g ) i s 9 × 10 - 10 . C a l c u l a t e ∆ G ° f o r t h e r e a c t i o n a t 25 ° C .

$K_{p} f o r t h e r e a c t i o n, M g C O_{3} (s) \to M g O (s) + C O_{2} (g) i s 9 \times 10^{- 10} . C a l c u l a t e ∆ G ° f o r t h e r e a c t i o n a t 25 ° C .$