Lesson no 14
Factorization
Dear Student
a(4a - b) + 2b(4a - b) - c(4a - b)
Taking (4a - b) as common:
(4a - b) {a + 2b - c}
So, a(4a - b) + 2b(4a - b) - c(4a - b) = (4a - b)(a + 2b - c)
Regards
a(4a - b) + 2b(4a - b) - c(4a - b)
Taking (4a - b) as common:
(4a - b) {a + 2b - c}
So, a(4a - b) + 2b(4a - b) - c(4a - b) = (4a - b)(a + 2b - c)
Regards