# Let A, B be the centres of two circles of equal radii; draw them so that each one of them passes through the centre of the other. Let them intersect at C and D.Examine whether and are at right angles.The answer is Let us draw two circles of same radius which are passing through the centres of the other circle. Here, point A and B are the centres of these circles and these circles are intersecting each other at point C and D.In quadrilateral ADBC,AD = AC (Radius of circle centered at A)BC = BD (Radius of circle centered at B)As radius of both circles are equal, therefore, AD = AC = BC = BDHence, is a rhombus and in a rhombus, the diagonals bisect each other at 90°. Hence, and are at right angles. But I think they form perpendicular bisectors and not right angle . So what would be the correct answer ?

Dear Student,

If the diagonals are perpendicular bisector then it means that both are inclined at an angles of 90° (which is a right angle) and also bisect each other i.e., if AB and CD intersect at O  then AO = OB and OC = OD.

Hope you get it!!

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