Let (a1,a2,a3,a4,a5) denote a rearrangement of (3,-5,7,4,-9) then the equation a1x4+a2x3+a3x2+a4x+a5=0 has how many roots - Maths - Logs Equations and Inequalities

Question

Let
(a1,a2,a3,a4,a5)
denote a rearrangement of (3,-5,7,4,-9) then the equation
a1x4+a2x3+a3x2+a4x+a5=0
has how many roots?

Rahul Raj · Accepted Answer

dear student

a1x4+a2x3+a3x2+a4x+a5=0for x=1a1+a2+a3+a4+a5=0for the given set of numberssum=3-5+7+4-9=0so, a1+a2+a3+a4+a5=0 for any set of arrangementhence, x=1 is always a root of the equation

regards

Let (a1,a2,a3,a4,a5) denote a rearrangement of (3,-5,7,4,-9) then the equation a1x4+a2x3+a3x2+a4x+a5=0 has how many roots?

Let (a₁,a₂,a₃,a₄,a₅) denote a rearrangement of (3,-5,7,4,-9) then the equation a₁x⁴+a₂x³+a₃x²+a₄x+a₅=0 has how many roots?