Let complex number alpha and 1/alphabar lie on circles (x-x0)^2 + (y-y0)^2=r^2 and (x-x0)^2 + (y-y0)^2=4r^2 respectively. If z0=x0+iy0 satisfies eq. 2|z0|^2=r^2 + 2, then |alpha|=? [1/rt7] Share with your friends Share 2 Shivam Mishra answered this Dear Student, Regards -5 View Full Answer