Let f and g be two real valued functions, defined by, f(x)=x^2 , g(x)=3x+2
Find:- (f+g)(-2); (f-g)(1); (fg)(-1)

We have,fx=x2 and gx=3x+2i f+g-2=f-2+g-2=-22+3×-2+2=4-6+2=0ii f-g1=f1-g1=12+3×1+2=1+3+2=6iii fg-1=f-1×g-1=-12×3×-1+2=1×-3+2=-1iv fg0=f0÷g0=02÷3×0+2=0÷0+2=0÷2=0

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