Let f(x) = sin x|sin x + sin 3x| , thena) . f(x) greater than equal to 0, when x is greater than equal to 0 b). f(x) is less than equal to 0 for all real values of x. c). f(x) is greater than equal to 0 for all real x. d). f(x) is less than equal to 0, when x is less than equal to 0. Share with your friends Share 4 Anuradha Sharma answered this We have,fx = sin xsin x + sin 3x=sin xsin x + 3 sin x - 4sin3x=sin x4 sin x - 4 sin3x=4 sin2x1 - sin2x= 4 sin2 x . cos2x=2 sin x . cos x2=sin 2x2Now, sin 2x2 ⩾0 as it is a square quantity ∀ x∈R.Hence, fx ⩾0 ∀ x∈R Hence option (c) is correct. 4 View Full Answer