Let f(x) = sin x|sin x + sin 3x| , then
a) . f(x) greater than equal to 0, when x is greater than equal to 0

b). f(x) is less than equal to 0 for all real values of x.

c). f(x) is greater than equal to 0 for all real x.

d). f(x) is less than equal to 0, when x is less than equal to 0.

We have,fx = sin xsin x + sin 3x=sin xsin x + 3 sin x - 4sin3x=sin x4 sin x - 4 sin3x=4 sin2x1 - sin2x= 4 sin2 x . cos2x=2 sin x . cos x2=sin 2x2Now, sin 2x2 0 as it is a square quantity  xR.Hence, fx 0  xR

Hence option (c) is correct.
 

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