let g(x)=1+x-[x] and f(x)={-1, x<o  0, x=0  1, x>0 } find fog

Dear student
When , -1<x<0Then, g(x)=1+x-x=1+x-(-1)=2+xfgx=1When x=0Then g(x)=1+x-x=1+x-0=1+xfgx=1When, x>1Then, g(x)=1+x-x=1+x-1=xfgx=1Therefore, for each interval fgx=1
Regards

  • 10
What are you looking for?