let me know why water escape and also its solutionlet me know why water escape and also its solution •es/Joint Package (ourse/Jtt (AO es en A thin walled hemispherical shell of mass m and radius R is pressed against a smooth vertical wall. Through a very small aperture at its top water of density p is filled in it completely. Minimum magnitude of force is to be applied to the shell for liquid not to escape from it. Weight of hemispherical shell is mg and total mass of water is M = — ltR3p . (A) Horizontal component of net force is —TtR3pg 9 mM)2 (B) Net extemal force is Mg —+ 1+— (C) Vertical component of force is (M + m)g , where 0 is from horizontal direction. (D) Direction of net force is given by 0 = arc tan 3M I mg M = Share with your friends Share 18 Sanjay Singh answered this Dear student Horizontal component of force =Pave×Vertical projected areahere vertical projected area is circular of radius R and average pressure is the pressure at the centre of the circle.Pave=ρgR area of projected circle in verticle plane =πR2Fhorizontal=ρgR×πR2=πρgR3M=23πR3ρπR3ρ=3M2Fhorizontal=3Mg2Net vertical force FV=(m+M)gNet force applied F=F2H+F2VF=(3Mg2)2+(m+M)2g2=(9M2g24)+(m+M)2g2=Mg94+(1+mM)2angle mede by the resultant with horizontal is tanθ=FVFH=(m+M)g3Mg2=2(m+M)3Mθ=tan-1(2(m+M)3M)Regards 4 View Full Answer
let me know why water escape and also its solution