Let PT be a tangent to the circle from an external point P and a secant to the circle through P intersects the circle at points A and B, then PT 2 = PA × PB

Using the above result prove thr following.

Triangle ABC is an isoceles triangle , such that AB = BC ,and the point D is the mid-point of AC . A circle is drawn taking BD as diameter, which intersects AB at E , prove that ..

AE = 1/4AC

Its urgent Please help Sir

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hi frnd . draw the disgram  by ur own . 

now  ad 2   = ae .  ab

  ad . ad = ae . bc

  ad . dc = ae . bc

4  ae = ac

 ae = 14 ac

hence prooved

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how???? this

4 ae = ac

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