let the opposite angular points of a square ABCD be A(3,4) C(1,-1).find C and D

Dear Student!

ABCD is a square. Coordinates of vertices A and C are (3, 4) and (1, –1) respectively.

Let the coordinate of vertex B be (*x, y*).

AB = BC (**Sides of the square are equal**)

Squaring on both sides, we get

In right ΔABC,

AB^{2} + BC^{2} = CA^{2}

When , we have

When , we have

Thus, the other vertices of the square are .

Cheers!

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