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Let x be the universal set for sets A and B. If n(a)=200 and n(B)=300 and n(A intersection B)=100, then n(A' intersection B') is equal to 300 provided n(x) is equal to

(A) 400
(B) 700
(C) 800
(D) 900

The correct answer is (B) 700. n(A) + n(B) - n(A intersection B) = n(A union B).
When you find A union B using this formula, it comes out to be 400. So i THINK it should be 700.
But somehow I feel I am missing out on something.
 

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Ans.   (b) 700.

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The correct answer is (B) 700. n(A' intersection B') = n(A union B) '=300 n(A) + n(B) - n(A intersection B) = n(A union B). When you find A union B using this formula, it comes out to be 400. Then U= n(A union B) +n(A union B)' i.e. U=400+300=700
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The correct answer is (B) 700. n(A' intersection B') = n(A union B) '=300 n(A) + n(B) - n(A intersection B) = n(A union B). When you find A union B using this formula, it comes out to be 400. Then U= n(A union B) +n(A union B)' i.e. U=400+300=700
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