Let y = mx + 5 is a line. Then the range of m so that points (5,6) and (-6,6) always lie on opposite side of origin is

a). m > 1/5 and m<-1/6
b). -1/6< m < 1/5
c). m>1/5
d). None of these

Dear Student,
Please find below the solution to the asked query:

We haveP5,6 and Q-6,6y=mx+5L1:mx-y+5=0When we put originL10,0=0-0+5=5>0As L10,0>0, hence for Pand Q to be on opposite side of origin,L1P<0 and L2Q<05m-6+5<0 and -6m-6+5<05m<1 and 6m>-1m<15 and m>-16Taking intersectioncommon values of m, we get-16<m<15 Optionb

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