Let a → = i ^ + j ^ + k ^ , b → = i ^ and c ^ = c 1 i ^ + c 2 j ^ + c 3 k ^ . Then , (i) If c 1 = 1 and c 2 = 2, find c 3 which makes a , → b → and c → coplanar. (ii) If c 2 = −1 and c 3 = 1, show that no value of c 1 can make a , → b → and c → coplanar. Share with your friends Share 0 Global Expert answered this i If c1=1 and c2=2, then a→=i^+j^+k^, b→=i^ and c^=i^+2j^+c3k^.We know that vectors a→, b→, c→ are coplanar iff a→ b→ c=0.It is given that a→, b→, c→ are coplanar.∴ a→ b→ c = 0⇒ 11110012c3=0 ⇒10-0-1c3-o+12-0=0⇒-c3 + 2=0⇒c3=2ii If c2=-1 and c3=1, then a→=i^+j^+k^, b→=i^ and c^=c1i^-j^+k.^We know that vectors a→, b→, c→ are coplanar iff a→ b→ c=0.For a→, b→, c→ to be coplanar:⇒a→ b→ c = 0⇒111100c1-11=0 ⇒10-0-11-0+1-1-0=0⇒-1-1=0⇒-2=0But this is never possible, whatever be the value of c1. Thus, no vaue of c1 can make a→, b→ and c→ coplanar. 1 View Full Answer