Let ABCDEF be a regular hexagon If AD→=xBC→ and CF→=yAB→, then xy=(1) 4(2) -4(3) 2(4) -2 - Maths - Introduction to Three Dimensional Geometry

Question

L e t   A B C D E F   b e   a   r e g u l a r
  h e x a g o n   I f   A D → = x B C →
  a n d   C F → = y A B → ,   t h e n
  x y = ( 1 )   4 ( 2 )   - 4 ( 3 )   2 ( 4 )
  - 2

Neha Sethi · Accepted Answer

Since It is a question of class XII , but i am providing you the
the similar link so that you can get the idea

https://www meritnation
com/ask-answer/question/in-a-regular-hexagon-abcdef-ab-vector-a-and-bc-vector-b/vector-algebra/7539207
Regards

L e t A B C D E F b e a r e g u l a r h e x a g o n . I f A D → = x B C → a n d C F → = y A B → , t h e n x y = ( 1 ) 4 ( 2 ) - 4 ( 3 ) 2 ( 4 ) - 2

$L e t A B C D E F b e a r e g u l a r h e x a g o n . I f \vec{A D} = x \vec{B C} a n d \vec{C F} = y \vec{A B}, t h e n x y = (1) 4 (2) - 4 (3) 2 (4) - 2$