L e t   A B C D E F   b e   a   r e g u l a r   h e x a g o n .   I f   A D = x B C   a n d   C F = y A B ,   t h e n   x y = ( 1 )   4 ( 2 )   - 4 ( 3 )   2 ( 4 )   - 2

Since It is  a question of class XII , but i am providing you the the similar link  so that you can get  the idea.
https://www.meritnation.com/ask-answer/question/in-a-regular-hexagon-abcdef-ab-vector-a-and-bc-vector-b/vector-algebra/7539207 
Regards

  • -3
its so easy
 
  • -3
What are you looking for?