Light of wavelength 3000 angstrom is incident on the metal surface, having work function 1 eV. Find the maximum velocity of emitted photo electron.

Hi Singh, recall h c/L - W = 1/2 m V2
​L - 3000 x 10-10 m
h = 6.626 x 10-34 J s
c = 3 x 10m/s
W - 1 eV = 1.6 x 10-19 J
m - mass of electron = 9 x 10-31 kg
Hope you would plug and get the value of V
V = max velocity of photo electron
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hc in ev is 12400A eV

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