Light of wavelength 4000 A is incident on a metal plate work function is 2 eV. What is maximum kinetic energy of emitted photoelectron? (1) 2.0 eV (2) 1.1 eV (4) 1.5 eV (3) 0.5 eV Share with your friends Share 1 Shobhit Mittal answered this work function ϕ=2 eV λ=4000 Amaximum KE=hcλ-ϕ=4.136*10-15*3*1084000*10-10-2=1.1 eV is the maximum KE of the photo electron.Regards 1 View Full Answer