Light of wavelength 4000 A is incident on a metal plate work function is 2 eV. What is maximum kinetic energy of emitted photoelectron? (1) 2.0 eV (2) 1.1 eV (4) 1.5 eV (3) 0.5 eV

work function ϕ=2 eV λ=4000 Amaximum KE=hcλ-ϕ=4.136*10-15*3*1084000*10-10-2=1.1 eV  is the maximum KE of the photo electron.Regards

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