Light of wavelength 550 nm falls normally on a slit of width 22 . 0 × 10 - 5 c m . The angular position of the second minima from the central maximum will be (in radians): 1 π 8 2 π 4 3 π 6 4 π 12 Share with your friends Share 4 Shobhit Mittal answered this Dear Student,λ=550 nm , d=22*10-5 cm , sinθ=2λd=1100*10-922*10-7=12θ=π6The angular position of the second minima from the central maximum will be π6option 3Regards 16 View Full Answer