LiH bond order​

Dear Student

Lithium Hydride, LiH is an example of a heteronuclear molecule and the molecular orbital is explained below -



Lithium, Li has two occupied atomic orbitals as compared to that of hydrogen, H which owns only one. The lowest energy orbitals is Li with 1s configuration, so its electrons are held so tightly that it does not participate in bonding. Therefore, the 2s orbital of Li with form a bond with the 1s orbital of H and will form the sigma bond and antibonding orbitals. Li has total 4 e^- , out oh which 2 are retained in the 1s orbital and the remain two lies in the σ- orbital which forms the Li-H covalent bond. Therefore, 


Bond Order = $\frac{no. of e^{-} in (bonding MO - antibonding MO)}{2}$ = $\frac{2 - 0}{2} = \frac{2}{2 }= 1$

Regards