lim[1/6+1/62+1/63+...1/6n] is where x tends to infinity is a)1/5 b)1/6 c)-1/5 d)none of these Share with your friends Share 1 Anuradha Sharma answered this limn→∞16+162+163+.....+16n=16+162+163+.....+16n+.......∞Now this is a geometric progression with , first term = 16 and common ratio=16And sum of infinite GP=a1-r=161-16=15 1 View Full Answer Ritesh Yadav answered this it will become an infinite G.Psum=a/(1-r)=(1/6)/(1-1/6)=1/5 4