lim x---->0 sin^2 (x-5)tan(x-5)/ (x^2-25)(x-5)=

dear student

if question is limit x0limx0sin2(x-5)tan(x-5)(x2-25)(x-5)=sin2(0-5)tan(0-5)(02-25)(0-5)=sin2(-5)tan(-5)125if question is limit x5limx5sin2(x-5)tan(x-5)(x2-25)(x-5)=limx5sin2(x-5)tan(x-5)(x-5)(x+5)(x-5)=limx5sin2(x-5)tan(x-5)(x-5)2(x+5)=limx5sin(x-5)(x-5)2×tan(x-5)(x-5)×(x-5)(x+5)=1×1×5-55+5=0

regards

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