lim x---> pi sqrt(1-cosx)-sqrt(2)/sin^2 x lim x → π 1 - cos x - 2 sin 2 x Share with your friends Share 0 Mayank Gupta answered this Dear student , here is detailed solution to your querylimx→π 1-cosx - 2sin2x→Applying L'Hospitals rule , → limx→π d (1-cosx - 2)dxd(sin2x)dx→ limx→π 121-cosx.(sinx)2sinxcosx→ limx→π 14cosx1-cosxSubstituting x=π :⇒ 14cosπ1-cosπ = 14.(-1)1-(-1)⇒-142Regards. 1 View Full Answer