lim x---> pi sqrt(1-cosx)-sqrt(2)/sin^2 x

lim x---> pi sqrt(1-cosx)-sqrt(2)/sin^2 x sin

Dear student , here is detailed solution to your querylimxπ   1-cosx - 2sin2xApplying L'Hospitals rule ,  limxπ  d (1-cosx - 2)dxd(sin2x)dx limxπ  121-cosx.(sinx)2sinxcosx limxπ  14cosx1-cosxSubstituting x=π :  14cosπ1-cosπ = 14.(-1)1-(-1)-142Regards.

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