lim x tends to 0 2sinx- sin 2x ÷ x^3 ^ Share with your friends Share 4 Varun.Rawat answered this lim x→0 2 sin x - sin 2xx3=limx→0 2 sin x - 2 sin x . cos xx3=limx→0 2 sin x 1 - cos xx3=limx→0 2 sin x . 2 sin2x/2x3=4 limx→0 sin xx ×12 limx→0 sinx/2x/2 × 12 limx→0 sinx/2x/2=4 × 1 × 12 × 1 × 12 × 1=1 19 View Full Answer
