lim (x tends to 0) [{root(x^2+1) -1}]/[{root(x^2+9) -3}] = ? Share with your friends Share 0 Ishwarmani answered this Dear Student, Please find below the solution to the asked query: limx→0x2+1-1x2+9-3=limx→0x2+1-1x2+9-3×x2+9+3x2+9+3=limx→0x2+1-1x2+9+3x2+9-9=limx→0x2+1-1x2+9+3x2×x2+1+1x2+1+1=limx→0x2+1-1x2+9+3x2x2+1+1=limx→0x2x2+9+3x2x2+1+1=limx→0x2+9+3x2+1+1=0+9+30+1+1=3+31+1=62=3 Regards 2 View Full Answer