lim x tends to 0...x-sinx/1-cosx

\lim_{x \to 0} \frac{x - sinx}{1 - cosx} This is \frac{0}{0} form Using L Hopitals rule \underset{x \to 0}{= \lim} \frac{\frac{d}{dx} (x - sinx)}{\frac{d}{dx} (1 - cosx)} = \lim_{x \to 0} \frac{1 - cosx}{sinx} This is \frac{0}{0} form Using L Hopitals rule again = \lim_{x \to 0} \frac{sinx}{cosx} = 0

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